In a Cinema hall, the distance between the projector and the screen is increased by 2%. Then the intensity of illumination on the screen is
Answer: B
The illumination is decreased by about 4 per cent.
Intensity obeys the inverse-square law, \(I \propto 1/d^2\), so \[\frac{\Delta I}{I} = -2\,\frac{\Delta d}{d} = -2 \times 2\% = -4\%\] Doubling the distance would cut the illumination to a quarter.
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