Discussion
A ball is thrown vertically upwards. Assuming the air resistance to be constant and considerable:
Answer: A
The time of ascent is less than the time of descent.
Air resistance always opposes motion. Going up it acts downwards, so the retardation is \(g + a\) and the ball slows faster; coming down it acts upwards, so the acceleration is only \(g - a\). The larger effective acceleration on the way up means less time is spent there.
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