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In the same Maxwell-Wien bridge, with \( R_4 = 10\ \)k\( \Omega \) and \( R_1 = R_2 R_3 / R_4 \), the resistance of the coil is

  • A.5 \( \Omega \)
  • B.20 k\( \Omega \)
  • C.50 \( \Omega \)
  • D.500 \( \Omega \)

Answer: C

The arithmetic is \( 1000 \times 500 / 10000 = 50\ \Omega \). Both parts of the balance come from the same set of readings, so a single balance yields the inductance and the resistance of the coil together, and from them its quality factor.

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