Discussion
In a bridge with arms \( Z_1 \), \( Z_2 \), \( Z_3 \) and \( Z_4 \) taken in order, the phase angles of the first three are \( +30^\circ \), \( -10^\circ \) and \( +50^\circ \). For balance the angle of the fourth arm must be
Answer: B
Opposite arms are the first with the fourth and the second with the third, so the condition is \( \theta_1 + \theta_4 = \theta_2 + \theta_3 \). Rearranging gives \( \theta_4 = -10 + 50 - 30 = +10^\circ \). The magnitude condition must hold at the same time before the detector will fall silent.
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