Discussion
Empirical formula \(\mathrm{CH_{2}O}\) will give the following compound for four number of its empirical formula .............
Answer: B
Four units of \(\mathrm{CH_{2}O}\) give \(\mathrm{C_{4}H_{8}O_{4}}\).
Multiplying the empirical formula by 4 multiplies each subscript by 4:
\[ (\mathrm{CH_{2}O})_{4} = \mathrm{C_{4}H_{8}O_{4}} \]
The ratio C : H : O stays 1 : 2 : 1. A tetrose sugar such as erythrose has this formula.
\(\mathrm{C_{4}H_{16}O_{4}}\) has twice the hydrogen of four \(\mathrm{CH_{2}O}\) units, and \(\mathrm{C_{4}H_{6}O_{6}}\) and \(\mathrm{C_{4}H_{10}O_{8}}\) do not have the 1 : 2 : 1 ratio at all.
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