Discussion
The number of electrons in \(\mathrm{Fe^{++}}\) is :
Answer: B
\(\mathrm{Fe^{++}}\) has 24 electrons.
Iron has atomic number 26, so a neutral iron atom has 26 electrons. The ferrous ion \(\mathrm{Fe^{2+}}\) is formed by losing two electrons (the two 4s electrons), leaving
\[ 26 - 2 = 24 \]
with configuration [Ar] 3d6.
26 is the neutral atom, 23 would be the ferric ion \(\mathrm{Fe^{3+}}\), and 18 and 16 do not correspond to any common ion of iron.
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