Discussion
63 g/mol HNO3 contains :
Answer: A
The 63 g contains \(6.022 \times 10^{23}\) HNO3 molecules.
The molar mass of nitric acid is
\[ 1 + 14 + 3 \times 16 = 63\ \text{g/mol} \]
so 63 g of HNO3 is exactly one mole, and one mole of any substance contains Avogadro's number of particles, \(6.022 \times 10^{23}\).
A single molecule weighs only about \(1.05 \times 10^{-22}\) g, so 1, 100 or 1000 molecules are vanishingly small masses, nowhere near 63 g.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development