Discussion
For \( \bar c = 3 \ \mathrm{m} \), \( V = 150 \ \mathrm{m/s} \) and a pitch rate of \( 0.20 \ \mathrm{rad/s} \), the non-dimensional pitch rate \( \hat q = q\bar c/2V \) is
Answer: C
Substituting into the standard normalisation:
\[ \hat q = \frac{0.20 \times 3}{2 \times 150} = 0.002 \]
so 0.002, a very small number, which is exactly the point: a rigid aeroplane manoeuvres at reduced frequencies far below unity, so quasi-steady aerodynamics is a good assumption. 0.004 forgets the factor of two in the denominator. 0.02 slips a decade. 0.0004 divides by the span instead of the chord in a way the definition does not permit.
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