Discussion
A reduced frequency is defined as \( k = \omega\bar c/2V \). For \( \omega = 3 \ \mathrm{rad/s} \), \( \bar c = 3 \ \mathrm{m} \) and \( V = 150 \ \mathrm{m/s} \), its value is
Answer: B
Substituting gives
\[ k = \frac{3 \times 3}{2 \times 150} = 0.03 \]
which is far below unity, so quasi-steady aerodynamics is justified for this short-period motion. That is the calculation behind the assumption rather than an assertion of it, and it is why flutter analysis, at much higher reduced frequency, cannot use the same derivative set. 0.06 omits the factor of two. 0.30 slips a decade. 0.003 divides by ten as well as by the factor.
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