Discussion
A feed of \( 5000 \) kg/h yields \( 3200 \) kg/h of product and \( 1800 \) kg/h of waste. The process yield is
Answer: D
Correct answer: 64.0 per cent
\[ \text{Yield} = \frac{3200}{5000} \times 100 = 64.0\% \]The waste stream, 1800 kg/h, accounts for the remaining 36 per cent - and the two streams sum to the feed, as a material balance requires.
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