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At a density ratio \( \sigma = 0.64 \), an equivalent airspeed of 200 knots corresponds to a true airspeed of

  • A.250 knots
  • B.160 knots
  • C.128 knots
  • D.313 knots

Answer: A

Correct answer: 250 knots

True airspeed follows from equivalent airspeed by dividing by the square root of the density ratio: \[ V_T = \frac{V_E}{\sqrt{\sigma}} = \frac{200}{\sqrt{0.64}} = \frac{200}{0.8} = 250\ \text{knots.} \] Multiplying instead of dividing gives 160 knots, which is offered as a distractor. True airspeed always exceeds equivalent airspeed at altitude, because the air is thinner, so the answer must be the larger number.

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