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Dynamic pressure at sea level density \( 1.225 \ \mathrm{kg/m^3} \) and a true airspeed of \( 100 \ \mathrm{m/s} \) is

  • A.1225 Pa
  • B.6125 Pa
  • C.12250 Pa
  • D.3063 Pa

Answer: B

Correct answer: 6125 Pa

\[ q = \tfrac{1}{2}\rho V^2 = 0.5 \times 1.225 \times 100^2 = 0.5 \times 1.225 \times 10\,000 = 6125\ \text{Pa.} \] Omitting the factor of one half gives 12 250 Pa, the other plausible distractor. This is the quantity the airspeed indicator actually responds to, which is why its reading depends on density as well as on speed.

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