Discussion
A flue gas desulphurisation plant removes \( 92 \) per cent of \( 24 \) tonnes a day of sulphur dioxide. The residual emission is
Answer: B
Correct answer: 1.92 tonnes
With 92 per cent removed, 8 per cent remains:
\[ 24 \times (1 - 0.92) = 24 \times 0.08 = 1.92\ \mathrm{tonnes\ per\ day} \]
The distractor \( 22.1 \) is the quantity removed rather than the residual, and \( 0.92 \) confuses the efficiency with a mass. Note how much a few percentage points of efficiency are worth at this scale: raising removal from 92 to 96 per cent would halve the residual emission again.
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