Discussion
A stack emits \( 40 \) g/s of particulate at a gas flow of \( 25 \) m\(^3\)/s. The concentration in the flue gas is
Answer: B
Correct answer: 1600 mg/m\(^3\)
Concentration is the mass emission rate divided by the volumetric gas flow:
\[ C = \frac{40\ \mathrm{g/s}}{25\ \mathrm{m^3/s}} = 1.6\ \mathrm{g/m^3} = 1600\ \mathrm{mg/m^3} \]
The unit conversion is where the marks are lost: a gram per cubic metre is a thousand milligrams per cubic metre. In practice the figure would also have to be corrected to reference conditions - a stated temperature, pressure and oxygen content - before it could be compared with an emission limit.
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