Discussion
A control device must bring \( 1600 \) mg/m\(^3\) down to \( 50 \) mg/m\(^3\). The required collection efficiency is
Answer: C
Correct answer: 96.9 per cent
Collection efficiency is the fraction of the inlet loading removed:
\[ \eta = \frac{C_{in} - C_{out}}{C_{in}} = \frac{1600 - 50}{1600} = 0.969 = 96.9\ \mathrm{per\ cent} \]
The distractor \( 3.1 \) is the fraction penetrating rather than collected. Note how demanding tight emission limits are: reaching \( 50 \) needs 96.9 per cent, but going to \( 20 \) would need 98.75 - a small change in the limit requiring a large change in the device.
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