Discussion
A boiler burns \( 12 \) tonnes of fuel an hour with an emission factor of \( 8.5 \) kg of nitrogen oxides per tonne. The hourly emission is
Answer: D
Correct answer: 102 kg
Multiply the emission factor by the fuel consumption:
\[ 12\ \mathrm{t/h} \times 8.5\ \mathrm{kg/t} = 102\ \mathrm{kg\ per\ hour} \]
The distractor \( 1020 \) misplaces a decimal and \( 70.8 \) divides rather than multiplies. Emission factors of this kind, tabulated by fuel and combustion technology, are what let an inventory estimate a plant's output from records that already exist - here the fuel purchase ledger.
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