Discussion
A skin panel \( 1.6 \) mm thick carries a shear flow of \( 120 \) kN/m. The shear stress in it is
Answer: A
Shear stress is the shear flow divided by the thickness, so \( 120\,000/0.0016 = 75 \times 10^6 \) Pa. Working in shear flow rather than stress is the habit of thin-walled analysis, because the flow is constant along a wall of varying thickness.
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