Discussion
Four stringers of \( 300 \) mm\( ^2 \) each sit at the corners of a box \( 0.5 \) m deep. Ignoring the skin, the second moment of area about the neutral axis is
Answer: C
Each of the four areas lies \( 0.25 \) m from the axis, so \( I = 4 \times 300 \times 10^{-6} \times 0.25^2 = 4 \times 3 \times 10^{-4} \times 0.0625 = 7.5 \times 10^{-5} \) m\( ^4 \). Booming off the stringers like this is the standard idealisation for a stiffened box.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development