Discussion
The product obtained on the reaction of propanone with CH3MgBr followed by hydrolysis is
Answer: A
The product is 2-Methylpropan-2-ol.
The methyl group of the Grignard reagent adds to the carbonyl carbon of propanone, and hydrolysis gives a tertiary alcohol:
\[ \begin{aligned} &(CH_{3})_{2}C=O + CH_{3}MgBr \\ &\xrightarrow{H_{2}O} (CH_{3})_{3}C-OH \end{aligned} \]
A ketone always gives a tertiary alcohol with a Grignard reagent, which rules out the primary alcohols (butan-1-ol, 2-methylpropan-1-ol) and the secondary butan-2-ol. 2-Methylpropane is an alkane, not an alcohol.
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