Discussion
(a - b)² =
Answer: A
\[ (a-b)^{2} = (a-b)(a-b) = a^{2} - ab - ab + b^{2} \]
\[ = a^{2} - 2ab + b^{2} \]
The middle term is essential: \( (a-b)^{2} \) is not \( a^{2} - b^{2} \), which factorises as \( (a+b)(a-b) \) instead.
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