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Answer of factorization of expression 4z(3a + 2b - 4c) + (3a + 2b - 4c) is

  • A.(4z + 1)(3a + 2b -4c)
  • B.(4z + 1) + (3a + 2b -4c)
  • C.(4z + 1) - (3a + 2b -4c)
  • D.(4z - 1)(3a - 2b -4c)

Answer: A

Both terms share the bracket \( (3a + 2b - 4c) \), so take it out as a common factor.

\[ 4z(3a+2b-4c) + 1 \cdot (3a+2b-4c) = (4z + 1)(3a + 2b - 4c) \]

The second term carries an invisible coefficient of 1, which is what becomes the \( +1 \) in the first bracket - dropping it would leave \( 4z(3a+2b-4c) \) alone.

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