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By factorizing expression 2bx + 4by - 3ax -6ay, answer must be

  • A.(2b + 3a)(x - 2y)
  • B.(2b - 3a)(x + 2y)
  • C.(2a- 3b)(3x - 2y)
  • D.(2a + 3b)(2x - 4y)

Answer: B

Group the terms in pairs and factor each.

\[ 2bx + 4by - 3ax - 6ay = 2b(x + 2y) - 3a(x + 2y) \]

The bracket \( (x + 2y) \) is now common:

\[ = (2b - 3a)(x + 2y) \]

Taking out \( -3a \) rather than \( 3a \) from the second pair is what makes both brackets identical.

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