Discussion

Answer of factorization of expression (3x - 2y)(a + b) + (4x - 3y)(a + b) is

Answer: D

Both terms share the factor \( (a + b) \), so take it out first:

\[ (3x - 2y)(a+b) + (4x - 3y)(a+b) = \left[(3x - 2y) + (4x - 3y)\right](a+b) \]

Collecting like terms inside the bracket:

\[ 3x + 4x = 7x, \qquad -2y - 3y = -5y \]

\[ \therefore\; (7x - 5y)(a + b) \]

The sign is the trap: both \( y \) terms are negative, so they add to \( -5y \) rather than cancelling.

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