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If a = 2, b = 4 and c =3 then 2ac[(2b + 3c)-c] is

  • A.11
  • B.51
  • C.168
  • D.12

Answer: C

Substitute \( a = 2 \), \( b = 4 \), \( c = 3 \) and work outward from the inner bracket.

\[ 2b + 3c = 8 + 9 = 17 \]

\[ 17 - c = 17 - 3 = 14 \]

\[ 2ac = 2 \times 2 \times 3 = 12 \]

\[ 12 \times 14 = 168 \]

The inner bracket must be evaluated before the multiplication by \( 2ac \).

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