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There are two numbers such that the sum of twice of the first and thrice of the second is 25, while the sum of thrice of the first and twice of the second is 20. The largest of the two is :

  • A.10
  • B.5
  • C.7
  • D.8

Answer: C

The larger number is 7.

Let the numbers be x and y:

\[ \begin{aligned} 2x + 3y &= 25 \\ 3x + 2y &= 20 \end{aligned} \]

Adding gives \(5x + 5y = 45\), so \(x + y = 9\); subtracting the first from the second gives \(x - y = -5\). Hence \(x = 2\) and \(y = 7\).

Check: \(4 + 21 = 25\) and \(6 + 14 = 20\). The larger of 2 and 7 is 7; 5 is their difference, and 10 and 8 do not satisfy the equations.

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