Discussion
One of the factors of \(20pq^{2} + 4pq + 45pr^{2} - 60pqr - 6rp\) is :
Answer: C
One factor is 2q - 3r.
Take out p, then group the terms:
\[ \begin{aligned} &p(20q^2 - 60qr + 45r^2 + 4q - 6r) \\ &= p[5(2q - 3r)^2 + 2(2q - 3r)] \\ &= p(2q - 3r)(10q - 15r + 2) \end{aligned} \]
So the factors are p, 2q - 3r and 10q - 15r + 2. Option 2, 2r - 3q, swaps the letters, and options 1 and 4 have p in place of q.
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