Discussion
One glass has juice and water in the ratio 5:2 while other glass has them in ratio 7:4, respectively. If both glasses poured in a vessel, then what will be final ratio of water to juice in the vessel?
Answer: D
Take one unit from each glass and add the parts.
\[ \text{water} = \frac{2}{7} + \frac{4}{11} = \frac{22 + 28}{77} = \frac{50}{77} \]
\[ \text{juice} = \frac{5}{7} + \frac{7}{11} = \frac{55 + 49}{77} = \frac{104}{77} \]
\[ \text{water} : \text{juice} = 50 : 104 = 25 : 52 \]
The question asks for water first, so the ratio is not the reciprocal 52 : 25 - which is offered as a distractor.
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