Discussion
How many liters of oil at Rs.40 per liter should be mixed with 240 liters of a second variety of oil at Rs.60 per liter so as to get a mixture whose cost is Rs.52 per liter?
Answer: D
Let \( x \) litres of the Rs. 40 oil be mixed with 240 litres of the Rs. 60 oil.
\[ \frac{40x + 60(240)}{x + 240} = 52 \]
\[ 40x + 14{,}400 = 52x + 12{,}480 \]
\[ 1920 = 12x \quad\Longrightarrow\quad x = 160 \text{ litres} \]
Alligation confirms it: \( \tfrac{x}{240} = \tfrac{60-52}{52-40} = \tfrac{8}{12} = \tfrac{2}{3} \), and \( \tfrac{2}{3} \times 240 = 160 \).
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development