Discussion
If \(A = Z = 1, B = Y = 2, C = X = 3, \ldots\) etc.
Which one is wrong?
Answer: D
With A = Z = 1, B = Y = 2 and so on, each letter takes the smaller of its place and its place from the end. M and N both have the value 13, so M = N is true, and M + N = 26 = L + O + A + Z = 12 + 12 + 1 + 1.
A + B + C = 6 = X + Y + Z is true. For E, G and J the values are 5, 7 and 10, and 10 is not prime, so the last statement is wrong, option D.
The code A to M gives the values 1 to 13 and N to Z the values 13 down to 1. So E, G and J have the values 5, 7 and 10, and of these only 5 and 7 are prime. Statement D is therefore wrong, and the three other statements are right.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development