Discussion
A receiver tuned to \( 800 \ \mathrm{kHz} \) with a \( 455 \ \mathrm{kHz} \) intermediate frequency and high-side injection has a local oscillator at
Answer: D
High-side injection puts the oscillator above the signal:
\[ f_{LO} = 800 + 455 = 1255 \ \mathrm{kHz} \]
giving 1255 kHz. The 345 kHz option is low-side injection, which works but needs a wider oscillator tuning ratio across the band. 455 kHz is the intermediate frequency and 800 kHz the signal. The choice of side also fixes where the image falls, which is the next thing any receiver designer checks.
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