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Upon hydrolysis of the pentapeptide Glu-Arg-Gly-Phe-Ala (represented from N- to C- terminus) with trypsin, the peptide fragments obtained are

  • A.Glu-Arg and Gly-Phe-Ala
  • B.Glu-Arg-Gly-Phe and Ala
  • C.Glu and Arg-Gly-Phe-Ala
  • D.Glu-Arg-Gly and Phe-Ala

Answer: A

Trypsin gives Glu-Arg and Gly-Phe-Ala.

Trypsin cuts on the carboxyl side of the basic residues lysine and arginine (unless the next residue is proline). In Glu-Arg-Gly-Phe-Ala the only basic residue is Arg at position 2, and it is followed by Gly, so the single cut falls between Arg and Gly.

Glu-Arg-Gly-Phe and Ala is a cut after Phe, which is chymotrypsin's preference for aromatic residues. Glu and Arg-Gly-Phe-Ala cuts on the wrong side of Arg. Glu-Arg-Gly and Phe-Ala cuts after Gly, which no common protease targets.

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