Machine-translated by Google. Questions are authored in English.
Top

Discussion

A speech signal occupying \( 300 \ \mathrm{Hz} \) to \( 3.4 \ \mathrm{kHz} \) amplitude modulates a carrier. The transmitted bandwidth is about

  • A.6.8 kHz
  • B.3.4 kHz
  • C.3.1 kHz
  • D.6.2 kHz

Answer: A

Bandwidth is twice the highest message frequency:

\[ B = 2 \times 3.4 = 6.8 \ \mathrm{kHz} \]

so 6.8 kHz, which is why AM broadcast channels are spaced at nine or ten kilohertz. 3.4 kHz is the message's own upper limit. 3.1 kHz is the message bandwidth, from 300 Hz to 3.4 kHz, which is not what sets the transmitted width because the sidebands are measured from the carrier. 6.2 kHz doubles the message bandwidth instead of the highest frequency, a subtle and common slip.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.