Discussion
A transmitter radiates \( 1000 \ \mathrm{W} \) of carrier and is modulated to \( \mu = 0.8 \). The total power is
Answer: D
Applying the power relation:
\[ \begin{aligned} P_t &= 1000\left(1 + \frac{0.64}{2}\right) \\ &= 1000 \times 1.32 = 1320 \ \mathrm{W} \end{aligned} \]
so 1320 watts. 1800 W would follow from using \( 1 + \mu \). 1080 W halves the sideband contribution twice over. 1640 W uses \( \mu^{2} \) without the factor of two. The sideband power here is 320 W in total, or 160 W in each sideband, which is the figure a sideband filter would have to handle.
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