Discussion
An AM transmitter draws an antenna current of \( 10 \ \mathrm{A} \) unmodulated. At \( \mu = 0.6 \) the current becomes about
Answer: C
Current follows the square root of power:
\[ \begin{aligned} I_t &= 10\sqrt{1 + \frac{0.36}{2}} \\ &= 10\sqrt{1.18} = 10.9 \ \mathrm{A} \end{aligned} \]
giving about 10.9 amperes. 11.8 A is the power ratio applied directly to the current, forgetting the root. 10.3 A halves the increase. 13.0 A corresponds to a much deeper modulation. Measuring the antenna current with and without modulation is the classic field method of determining the index.
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