Discussion
A receiver delivers \( 2 \ \mathrm{V} \) of carrier to its detector with an index of \( 0.5 \). The recovered audio amplitude is about
Answer: C
The envelope varies about the carrier level by the index times the carrier:
\[ V_{audio} = 0.5 \times 2 = 1 \ \mathrm{V} \]
so about 1 volt peak, ignoring the diode's forward drop and detector efficiency. 2 V is the carrier itself, which appears as a direct-current component rather than as audio. 0.5 V is the index quoted as a voltage. And 4 V exceeds the envelope maximum, which is 3 V here. Note that the recovered audio is proportional to both the index and the carrier level, which is why gain control is needed to keep the output steady.
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