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Which of the following complex numbers are collinear ?

  • A.\(1 + 2i, 2 + 5i, 4 + 11i\)
  • B.\(1 - i, 2 + i, 1 + i\)
  • C.\(i, -1 + 2i, 3 + 4i\)
  • D.\(0, -3 + i, 7 + 8i\)

Answer: A

The collinear points are \(1 + 2i, 2 + 5i, 4 + 11i\).

Three points \(z_{1}, z_{2}, z_{3}\) are collinear when \(z_{2} - z_{1}\) and \(z_{3} - z_{1}\) are real multiples of each other. Here

\[ \begin{aligned} z_{2} - z_{1} &= 1 + 3i \\ z_{3} - z_{1} &= 3 + 9i = 3(1 + 3i) \end{aligned} \]

so the points lie on the line \(y = 3x - 1\).

The other sets fail the test. For \(1 - i, 2 + i, 1 + i\) the differences are \(1 + 2i\) and \(2i\); for \(i, -1 + 2i, 3 + 4i\) they are \(-1 + i\) and \(3 + 3i\); for \(0, -3 + i, 7 + 8i\) they are \(-3 + i\) and \(7 + 8i\). In each case the ratio is not real.

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