Discussion
Molar extinction coefficient of malondialdehyde at 532 nm is 0.155 \(\mathrm{M^{-1}cm^{-1}}\). The concentration of malondialdehyde in a solution which has absorbance of 0.31 in a 1 cm curette will be
Answer: D
By the Beer-Lambert law, \(A = \varepsilon\,c\,l\). With \(A = 0.31\), \(\varepsilon = 0.155\), \(l = 1\) cm:
\[ c = \frac{A}{\varepsilon\, l} = \frac{0.31}{0.155 \times 1} \]
\[ c = 2.0 \]
The concentration is 2.0 M in the units of the coefficient given in the question. The values 0.5 M, 1.0 M and 1.5 M do not satisfy the equation.
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