Discussion
In a gas chromatography experiment, the retention factor (Rf ) values for pollutant 'A' and pollutant 'B' in a mixture of pollutants were 0.5 and 0.125, respectively. If the distance travelled by solvent front is 12 cms, the distance (in cms) travelled by pollutant 'A' and pollutant 'B' will be
Answer: A
The distance travelled by a pollutant is its Rf value multiplied by the distance travelled by the solvent front. For pollutant A this is \(0.5 \times 12 = 6\) cm, and for pollutant B it is \(0.125 \times 12 = 1.5\) cm.
\[ d = R_f \times 12 \]
So the distances are 6 and 1.5 cm, option A. Option C gives the Rf values instead of distances, option B uses 6 as 3 by an arithmetic slip, and option D swaps the two substances.
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