Discussion
The half power beamwidth of a uniform circular aperture is about \( 58\lambda/D \) degrees. What is it for D = 2 m at 10 GHz?
Answer: C
At 10 GHz the wavelength is 0.03 m, so:
\[ \theta \approx \tfrac{58 \times 0.03}{2} = 0.87 \]
degrees, that is about 0.87 degrees. A tapered illumination would widen this to around one and a quarter degrees while lowering the side lobes. The coefficient is 51 for a uniform line source, 58 for a uniform circular aperture and around 70 for a heavily tapered one, and quoting which convention is in use matters as much as the arithmetic itself.
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