Discussion
In an arc welding process, welding speed is doubled. Assuming all other process parameters to be constant, the cross sectional area of the weld bead will
Answer: D
The bead cross-section will reduce by 50%.
With all other parameters fixed, the volume of filler deposited per unit time is constant. The bead area times the welding speed equals that deposition rate, so the cross-sectional area is inversely proportional to the travel speed:
\[ A_{2} = A_{1}\frac{v_{1}}{v_{2}} = \frac{A_{1}}{2} \]
The heat input per unit length (VI/v) also halves for the same reason. A 25% reduction would correspond to a speed increase of one third, and the bead cannot grow when the same metal is spread over a longer length.
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