Discussion
A rhombus has one of its diagonal 60% of the other. A square is drawn using the longer diagonal as side. What will be ratio of area of square to that of the rhombus?
Answer: C
Let the longer diagonal be \( d \); the shorter is then \( 0.6d \).
A rhombus's diagonals bisect each other at right angles, so its area is half their product:
\[ A_{\text{rhombus}} = \frac{1}{2} \times d \times 0.6d = 0.3d^{2} \]
The square is built on the longer diagonal as its side:
\[ A_{\text{square}} = d^{2} \]
\[ \frac{A_{\text{square}}}{A_{\text{rhombus}}} = \frac{d^{2}}{0.3d^{2}} = \frac{10}{3} \quad\Longrightarrow\quad 10 : 3 \]
The unknown \( d \) cancels, so the ratio holds for any rhombus with that diagonal proportion.
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