Machine-translated by Google. Questions are authored in English.
Top

Discussion

If ratio of the areas of two squares is 1:4, the ratio of their perimeters is

  • A.1:2
  • B.1:4
  • C.1:6
  • D.1:8

Answer: A

Area varies as the square of the side, so take square roots to recover the length ratio.

\[ \frac{a_{1}^{2}}{a_{2}^{2}} = \frac{1}{4} \quad\Longrightarrow\quad \frac{a_{1}}{a_{2}} = \frac{1}{2} \]

Perimeter is \( 4a \), a plain multiple of the side, so it keeps that same ratio:

\[ \frac{P_{1}}{P_{2}} = \frac{4a_{1}}{4a_{2}} = \frac{1}{2} \quad\Longrightarrow\quad 1 : 2 \]

Carrying the area ratio straight through to the perimeters gives 1 : 4, the first distractor.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.