Discussion
What are the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad ?
Answer: C
Square tiles must divide both dimensions exactly, and the fewest tiles means the largest tile - the highest common factor.
\[ 15 \text{ m } 17 \text{ cm} = 1517 \text{ cm}, \qquad 9 \text{ m } 2 \text{ cm} = 902 \text{ cm} \]
\[ 1517 = 37 \times 41, \qquad 902 = 2 \times 11 \times 41 \]
\[ \text{HCF} = 41 \text{ cm} \]
\[ n = \frac{1517}{41} \times \frac{902}{41} = 37 \times 22 = 814 \]
The awkward 17 cm and 2 cm are deliberate: they force a common factor of 41 rather than a round number.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development