Discussion
A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?
Answer: B
Poles stand along the boundary, so first find its length.
\[ \text{perimeter} = 2(90 + 50) = 280 \text{ m} \]
\[ n = \frac{280}{5} = 56 \]
On a closed loop the number of gaps equals the number of poles - the last pole is 5 m from the first - so no "+1" is needed here. That extra pole is required only for a fence along an open line.
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