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A rectangular parking space is marked out by painting three of its sides. If the length of the unpainted sides is 9 feet, and  the sum of the length of the two painted sides is 37 feet, then what is the area of the parking space in square feet?

  • A.46 sq.ft
  • B.81 sq.ft
  • C.126 sq.ft
  • D.252 sq.ft

Answer: C

Three sides are painted and one is not. The unpainted side is 9 ft, so the side opposite it is also 9 ft and is painted, along with the two equal widths.

\[ 9 + 2w = 37 \quad\Longrightarrow\quad 2w = 28 \quad\Longrightarrow\quad w = 14 \text{ ft} \]

\[ A = 9 \times 14 = 126 \text{ ft}^{2} \]

The 37 ft covers all three painted sides, not two - reading it as the two widths alone would give \( w = 18.5 \) and an area of 166.5 ft².

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