Discussion

The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.

Answer: A

Check the triangle inequality before computing anything: the sum of any two sides must exceed the third.

\[ 1 + 2 = 3 \]

This is equality, not inequality, so the three points are collinear and no triangle encloses any area.

Heron's formula confirms it. With \( s = \tfrac{1+2+3}{2} = 3 \):

\[ A = \sqrt{3(3-1)(3-2)(3-3)} = \sqrt{3 \times 2 \times 1 \times 0} = 0 \]

The zero factor \( (s - c) \) is the algebra registering the degenerate case.

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