Discussion
The altitude of an equilateral triangle of side 2√3 cm is?
Answer: D
The altitude of an equilateral triangle splits it into two 30–60–90 triangles, giving
\[ h = \frac{\sqrt{3}}{2}a \]
\[ h = \frac{\sqrt{3}}{2} \times 2\sqrt{3} = \frac{2 \times 3}{2} = 3 \text{ cm} \]
Equivalently, by Pythagoras: \( \sqrt{(2\sqrt{3})^{2} - (\sqrt{3})^{2}} = \sqrt{12 - 3} = 3 \).
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development