Discussion
What is the area of a square field whose diagonal of length 20 m?
Answer: C
A square's diagonal and side satisfy \( d = a\sqrt{2} \), so
\[ a^{2} = \frac{d^{2}}{2} \]
\[ A = \frac{20^{2}}{2} = \frac{400}{2} = 200 \text{ m}^{2} \]
Squaring the diagonal without halving gives 400, offered as the last option; the diagonal cuts the square into two right triangles, and the halving reflects that.
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