Discussion
What is the perimeter of a square field whose diagonal is 8√2?
Answer: B
From \( d = a\sqrt{2} \):
\[ a = \frac{8\sqrt{2}}{\sqrt{2}} = 8 \]
\[ \text{perimeter} = 4a = 32 \text{ m} \]
The \( \sqrt{2} \) in the given diagonal is a deliberate signal that the side is a whole number.
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