Discussion
The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/8 of the area of the field. What is the length of the field?
Answer: B
Start from the pond, whose area is known outright.
\[ A_{\text{pond}} = 8^{2} = 64 \text{ m}^{2} \]
\[ A_{\text{field}} = 8 \times 64 = 512 \text{ m}^{2} \]
With \( l = 2w \):
\[ 2w^{2} = 512 \quad\Longrightarrow\quad w^{2} = 256 \quad\Longrightarrow\quad w = 16 \text{ m} \]
\[ l = 32 \text{ m} \]
The pond is one eighth of the field, so the field is eight times the pond - dividing instead of multiplying is the trap, and 16 m (the width) is offered for anyone who stops one step early.
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